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AdeMiller wrote May 12, 2011 at 2:42 PM
jsh003guardz63 wrote Jul 19, 2011 at 4:09 PM
jsh003guardz63 wrote Jul 19, 2011 at 4:10 PM
jsh003guardz63 wrote Jul 19, 2011 at 4:14 PM
jsh003guardz63 wrote Jul 19, 2011 at 4:17 PM
jsh003guardz63 wrote Jul 19, 2011 at 4:20 PM
S = the number of stages in figure 4 (= 4) N = the number of images in figure 4 (= 6) T = the duration to process one stage for one image (= t1 - t0 = t2 – t1)
The elapsed time for a completely parallel and completely efficient pipeline is (S+N-1) * T. The elapsed time taken for one stage = N * T.
(S+N-1) x T is only equal to N * T when S = 1.
jsh003guardz63 wrote Jul 19, 2011 at 4:22 PM
Niels_Dekker wrote Sep 1, 2011 at 3:15 PM
Niels_Dekker wrote Sep 1, 2011 at 3:44 PM
Niels_Dekker wrote Sep 22, 2011 at 10:17 AM
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